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Al Viro authored
passing *any* namespace root to __d_path() as root is equivalent to just passing it {NULL, NULL}; no need to bother with finding the root of our namespace in there. Signed-off-by:
Al Viro <viro@zeniv.linux.org.uk>
Al Viro authoredpassing *any* namespace root to __d_path() as root is equivalent to just passing it {NULL, NULL}; no need to bother with finding the root of our namespace in there. Signed-off-by:
Al Viro <viro@zeniv.linux.org.uk>